360=-16t^2+156t

Solution for 360=-16t^2+156t equation:

360=-16t^2+156t

We move all terms to the left:

360-(-16t^2+156t)=0

We get rid of parentheses

16t^2-156t+360=0

a = 16; b = -156; c = +360;
Δ = b2-4ac
Δ = -1562-4·16·360
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-156)-36}{2*16}=\frac{120}{32}
=3+3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-156)+36}{2*16}=\frac{192}{32}
=6
$